The capacitor of capacitance `4 muF` and `6 muF` are connected in series. A potential difference of `500` volts applied to the outer plates of the two capacitor system. Then the charge on each capacitor is numerically

Options

A. `6000 mu` C
B. `1200 mu`C
C. 1200 C
D. 6000 C

Explanation

To solve the problem of finding the charge on each capacitor when two capacitors of capacitance \(4 \mu F\) and \(6 \mu F\) are connected in series across a potential difference of \(500\) volts, we can follow these steps:

### Step 1: Calculate the Equivalent Capacitance
For capacitors in series, the equivalent capacitance \(C_{eq}\) can be calculated using the formula:

\[ \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} \]
...