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A series combination of `n_(1)` capacitors, each of value `C_(1)`, is charged by a source of potential difference 4V. When another parallel combination of `n_(2)` capacitors, each of value `C_(2)`, is charged by a source of potential difference V,it has the same (total) energy stored in it, as the first combination has. The value of `C_(2)`, in terms of `C_(1)`, is then

A

`(2C_(1))/(n_(1) n_(2))`

B

`16(n_(2))/(n_(1)) C_(1)`

C

`2 (n_(2))/(n_(1))C_(1)`

D

`(16 C_(1))/(n_(1)n_(2))`

Text Solution

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The correct Answer is:
D
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AAKASH INSTITUTE ENGLISH-ELECTROSTATIC POTENTIAL AND CAPACITANCE -ASSIGNMENT SECTION - C
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