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A condenser of capicity C is charged to ...

A condenser of capicity C is charged to a potential difference of `V_(1)`. The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to `V_(2)` is -

A

`((C(V_(1) - V_(2))^(2))/(L) )^(1//2)`

B

`(C(V_(1)^(2) - V_(2)^(2)))/(L) `

C

`(C(V_(1)^(2) + V_(2)^(2)))/(L)`

D

`((C(V_(1)^(2) - V_(2)^(2)))/(L) )^(1//2)`

Text Solution

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The correct Answer is:
D
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