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An electric dipole of moment p is palced...

An electric dipole of moment `p` is palced in the positive of stable equilibrium in uniform electric field of intensity `E`. It is rotated through an angle `theta` from the initial position. The potential energy of electric dipole in the final position is

A

`-`pE cos `theta`

B

pE `(1 - cos theta)`

C

pE cos `theta`

D

pE sin `theta`

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The correct Answer is:
To find the potential energy of an electric dipole in a uniform electric field after it has been rotated through an angle θ, we can follow these steps: ### Step 1: Understand the Initial Position Initially, the electric dipole (with dipole moment \( p \)) is aligned parallel to the electric field \( E \). In this position, the potential energy \( U_i \) of the dipole is at its minimum value, which is given by: \[ U_i = -p \cdot E = -pE \cos(0) = -pE \] Here, the angle between the dipole moment and the electric field is \( 0^\circ \). ### Step 2: Determine the Final Position After the dipole is rotated through an angle \( \theta \), the angle between the dipole moment and the electric field becomes \( \theta \). ### Step 3: Calculate the Potential Energy in the Final Position The potential energy \( U_f \) of the dipole in the electric field when it makes an angle \( \theta \) with the field is given by the formula: \[ U_f = -p \cdot E = -pE \cos(\theta) \] This formula arises from the dot product of the dipole moment vector and the electric field vector. ### Step 4: Conclusion Thus, the potential energy of the electric dipole in the final position after being rotated through an angle \( \theta \) is: \[ U_f = -pE \cos(\theta) \] ### Final Answer The potential energy of the electric dipole in the final position is \( -pE \cos(\theta) \). ---
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