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A capacitor of capacity C(1), is charged...

A capacitor of capacity `C_(1)`, is charged by connecting it across a battery of emf `V_(0)`. The battery is then removed and the capacitor is connected in parallel with an uncharged capacitor of capacity `C_(2)`. The potential difference across this combination is

A

`(C_(2)V)/(C_(1) + C_(2))`

B

`(C_(1)V)/(C_(1) + C_(2))`

C

`( 1 + (C_(2))/(C_(1)))`V

D

`(1 - (C_(2))/(C_(1)) ) V `

Text Solution

Verified by Experts

The correct Answer is:
B
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AAKASH INSTITUTE ENGLISH-ELECTROSTATIC POTENTIAL AND CAPACITANCE -ASSIGNMENT SECTION - C
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