`CH_(3) CH_(2)Cl+Ag_(2)O overset(Delta)to ` Product . Product formed in the reaction is

Options

A. `CH_(3) CH_(2) - O - CH_(2) CH_(3)`
B. `CH_(3) CH_(2) Cl + AgCl`
C. `CH_(3) CH_(2) - OH + AgCl`
D. `(CH_(3) CH_(2) - O)_(2) Ag`

Answer

To solve the question regarding the reaction of ethyl chloride (CH₃CH₂Cl) with silver oxide (Ag₂O) upon heating, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are:
- Ethyl chloride (CH₃CH₂Cl)
- Silver oxide (Ag₂O)

### Step 2: Understand the Reaction Type
When an alkyl halide (like ethyl chloride) reacts with a metal oxide (like silver oxide), it typically undergoes a reaction that leads to the formation of an ether. This is because the alkyl halide can react with the oxide to form an ether and a halide salt.

### Step 3: Write the Reaction
The reaction can be represented as follows:
\[ \text{CH}_3\text{CH}_2\text{Cl} + \text{Ag}_2\text{O} \xrightarrow{\Delta} \text{CH}_3\text{CH}_2\text{OCH}_2\text{CH}_3 + 2\text{AgCl} \]

### Step 4: Identify the Products
From the reaction, we can see that:
- The ether formed is diethyl ether (CH₃CH₂OCH₂CH₃).
- Silver chloride (AgCl) is also formed as a byproduct.

### Step 5: Conclusion
The product formed in the reaction between ethyl chloride and silver oxide upon heating is diethyl ether (CH₃CH₂OCH₂CH₃) along with silver chloride (AgCl).

### Final Answer
The product formed in the reaction is:
\[ \text{CH}_3\text{CH}_2\text{OCH}_2\text{CH}_3 \]

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