`CH_(3)underset(CH_(3))underset(|)(CH)-CH=CH_(2)underset((ii)H_(2)O_(2)//OH)overset((i)B_(2)H_(4))toXunderset(140^(@))overset(H_(2)SO_(4))toY`
What is Y ?

Options

A. `CH_(3) -underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)-O-CH_(2)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(3)`
B. `CH_(3) -underset(CH_(3))underset(|)(CH)-CH=CH_(2)`
C. `CH_(3)-underset(CH_(3))underset(|)(CH)-underset(CH_(3))underset(|)(CH)-O-underset(CH_(3))underset(|)(CH)-underset(CH_(3))underset(|)(CH)-CH_(3)`
D. `CH_(3)-underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-O-underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)`

Answer

To solve the question, we need to follow the steps of the reaction as described in the video transcript. Let's break it down step by step:

### Step 1: Identify the Starting Material
The starting compound is:
\[ \text{CH}_3\text{CH}(\text{CH}_3)\text{CH}(\text{CH}_2)\text{CH}=\text{CH}_2 \]
This compound has a double bond between the last two carbon atoms.

### Step 2: Hydroboration with B2H6
The compound is treated with diborane (\( \text{B}_2\text{H}_6 \)), which is a reagent used in hydroboration. This step involves the addition of boron and hydrogen across the double bond.

In hydroboration, the addition occurs in an anti-Markovnikov fashion, meaning that the boron atom will attach to the less substituted carbon (the one with more hydrogen atoms).

### Step 3: Oxidation with H2O2/OH⁻
After hydroboration, the compound is treated with hydrogen peroxide (\( \text{H}_2\text{O}_2 \)) in the presence of hydroxide ions (\( \text{OH}^- \)). This step converts the boron intermediate into an alcohol.

The final product \( X \) after hydroboration and oxidation will be:
\[ \text{CH}_3\text{CH}(\text{CH}_3)\text{CH}_2\text{CH}_2\text{OH} \]
This is a primary alcohol.

### Step 4: Dehydration with H2SO4
Next, the alcohol \( X \) is treated with sulfuric acid (\( \text{H}_2\text{SO}_4 \)) at 140 degrees Celsius. This step leads to dehydration, where water is removed from the alcohol, resulting in the formation of an ether.

### Step 5: Formation of Ether
When two molecules of the alcohol are dehydrated, they can form an ether. The reaction can be represented as:
\[ 2 \text{CH}_3\text{CH}(\text{CH}_3)\text{CH}_2\text{CH}_2\text{OH} \xrightarrow{\text{H}_2\text{SO}_4, 140^\circ C} \text{Ether} \]

The ether formed will be:
\[ \text{CH}_3\text{CH}(\text{CH}_3)\text{CH}_2\text{CH}_2\text{O}\text{CH}_2\text{CH}_2\text{CH}(\text{CH}_3)\text{CH}_3 \]

### Conclusion
Thus, the final product \( Y \) is an ether formed from the dehydration of the alcohol.

### Final Answer
\[ Y = \text{Ether} \]