When phenol is treated with `CHCl_(3)` and `NaOH`, the product fromed is

Options

A. Benzaldehyde
B. Salicylaldehyde
C. Salicylic acid
D. Benzoic acid

Answer

To solve the question of what product is formed when phenol is treated with CHCl₃ and NaOH, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are phenol (C₆H₅OH), chloroform (CHCl₃), and sodium hydroxide (NaOH).

2. **Recognize the Reaction Type**: This reaction is known as the Reimer-Tiemann reaction, which is a well-known reaction in organic chemistry that involves the ortho-formylation of phenols.

3. **Formation of Sodium Phenoxide**: When phenol is treated with NaOH, it forms sodium phenoxide (C₆H₅O⁻Na⁺). This is because NaOH deprotonates phenol, resulting in the formation of the phenoxide ion.

4. **Chloroform Reaction**: The sodium phenoxide then reacts with chloroform (CHCl₃) in the presence of NaOH. This step involves the formation of a dichloromethyl intermediate.

5. **Formation of Salicylaldehyde**: The reaction proceeds with the elimination of HCl and water, leading to the formation of salicylaldehyde (C₆H₄(OH)CHO), also known as 2-hydroxybenzaldehyde.

6. **Final Product**: The final product of the reaction is salicylaldehyde.

### Final Answer:
When phenol is treated with CHCl₃ and NaOH, the product formed is salicylaldehyde (2-hydroxybenzaldehyde).

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