A : The reactivity order of alcohols is `1^(@) gt 2^(@) gt 3^(@)` for the reaction in which O-H bond is broken .
R : The reactivity order of alcohol is `3^(@) gt 2^(@) gt 1^(@)` for the reaction in which C - O bond is broken .

Options

A. If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)
B. If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)
C. If Assertion is true statement but Reason is false , then mark (3)
D. If both Assertion and Reason are false statements , then mark (4)

Answer

To solve the question, we need to analyze both the assertion (A) and the reason (R) regarding the reactivity order of alcohols when different bonds are broken.

### Step 1: Analyze the Assertion (A)
The assertion states that the reactivity order of alcohols is:
\[ 1^\circ > 2^\circ > 3^\circ \]
for the reaction in which the O-H bond is broken.

**Explanation:**
- When the O-H bond is broken, the alcohol acts as an acid, and the stability of the resulting alkoxide ion (RO⁻) is crucial.
- In primary alcohols (1°), there is less steric hindrance and less +I (inductive) effect from alkyl groups, making the alkoxide ion more stable.
- In secondary alcohols (2°), there is moderate steric hindrance and +I effect, leading to moderate stability of the alkoxide ion.
- In tertiary alcohols (3°), there is significant steric hindrance and a strong +I effect, which destabilizes the alkoxide ion.

Thus, the order of reactivity when the O-H bond is broken is indeed:
\[ 1^\circ > 2^\circ > 3^\circ \]
This means the assertion is **true**.

### Step 2: Analyze the Reason (R)
The reason states that the reactivity order of alcohols is:
\[ 3^\circ > 2^\circ > 1^\circ \]
for the reaction in which the C-O bond is broken.

**Explanation:**
- When the C-O bond is broken, the alcohol behaves as a base, forming a carbocation (R⁺).
- Tertiary carbocations (3°) are the most stable due to hyperconjugation and inductive effects from surrounding alkyl groups.
- Secondary carbocations (2°) are less stable than tertiary but more stable than primary.
- Primary carbocations (1°) are the least stable due to having only one alkyl group to stabilize the positive charge.

Thus, the order of reactivity when the C-O bond is broken is:
\[ 3^\circ > 2^\circ > 1^\circ \]
This means the reason is also **true**.

### Step 3: Conclusion
Both the assertion and the reason are true. However, the reason does not explain the assertion correctly. The assertion discusses the stability of alkoxide ions, while the reason discusses the stability of carbocations.

### Final Answer
Both assertion and reason are true, but the reason is not the correct explanation of the assertion. Therefore, the correct option is:
**Option 2: Both assertion and reason are true, but the reason is not the correct explanation of the assertion.**

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