The precipitate formed by mixing silver nitrate and sodium chloride disappears on adding ethylamine. It is due to the formation of

Options

A. `C_2H_5Cl`
B. `C_2H_5NO_2`
C. `[Ag(C_2H_5NH_2)_2]Cl`
D. `CH_3COCl`

Answer

To solve the question regarding the disappearance of the precipitate formed by mixing silver nitrate and sodium chloride upon the addition of ethylamine, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**:
When silver nitrate (AgNO3) is mixed with sodium chloride (NaCl), a precipitation reaction occurs:
\[ \text{AgNO}_3 + \text{NaCl} \rightarrow \text{AgCl (s)} + \text{NaNO}_3 \]
Here, silver chloride (AgCl) is formed as a white precipitate.

2. **Recognize the Precipitate**:
The precipitate formed is silver chloride (AgCl), which is insoluble in water.

3. **Introduce Ethylamine**:
When ethylamine (C2H5NH2) is added to the mixture containing the precipitate, a complexation reaction occurs.

4. **Formation of the Complex**:
Ethylamine acts as a ligand and coordinates with silver ions (Ag+). The reaction can be represented as:
\[ \text{AgCl (s)} + 2 \text{C}_2\text{H}_5\text{NH}_2 \rightarrow [\text{Ag}(\text{C}_2\text{H}_5\text{NH}_2)_2]^+ + \text{Cl}^- \]
This results in the formation of a soluble complex, specifically diethylamine silver(I) chloride.

5. **Dissolution of the Precipitate**:
The formation of the soluble complex leads to the dissolution of the previously formed AgCl precipitate. Therefore, the precipitate disappears.

6. **Conclusion**:
The disappearance of the precipitate is due to the formation of the soluble complex, diethylamine silver(I) chloride.

### Final Answer:
The precipitate formed by mixing silver nitrate and sodium chloride disappears on adding ethylamine due to the formation of diethylamine silver(I) chloride.