Isopropylamine `overset(KMnO_(4))rarr X overset(H_(3)^(+)O)rarr Y`
In the above sequence X and Y are

Options

A. Acetaldehyde, Ethanal
B. Ethanal, Ketimine
C. Ketimine, Acetone
D. Acelone, Propan-2-ol

Answer

To solve the problem, we need to determine the products X and Y formed from the reaction of isopropylamine with potassium permanganate (KMnO4) followed by treatment with hydronium ion (H3O+).

### Step-by-Step Solution:

1. **Identify the Structure of Isopropylamine**:
- Isopropylamine has the chemical structure:
\[ \text{CH}_3\text{CH}(\text{NH}_2)\text{CH}_3 \]
- This can also be represented as:
\[ \text{(CH}_3)_2\text{CHNH}_2 \]

2. **Oxidation with KMnO4**:
- When isopropylamine is treated with KMnO4, it undergoes oxidation. In this process, hydrogen atoms are removed from the nitrogen and the adjacent carbon atoms.
- The oxidation will convert the amine group into an imine group, resulting in the formation of a compound known as ketamine.
- The structure of the product (X) after oxidation can be represented as:
\[ \text{CH}_3\text{C}(\text{CH}_3)=\text{NH} \]
- This compound is called **ketamine**.

3. **Hydrolysis with H3O+**:
- The next step involves treating the ketamine with hydronium ions (H3O+), which leads to hydrolysis.
- During hydrolysis, the double bond between the carbon and nitrogen is broken, and a carbonyl group (C=O) is formed.
- The hydrolysis of ketamine results in the formation of acetone (Y) and ammonia (NH3) as a byproduct.
- The structure of the product (Y) is:
\[ \text{CH}_3\text{C}(\text{O})\text{CH}_3 \]
- This compound is known as **acetone**.

4. **Final Products**:
- Therefore, the final products of the reaction sequence are:
- **X = Ketamine**
- **Y = Acetone**

### Summary of the Solution:
- X is **Ketamine** (formed from isopropylamine by oxidation with KMnO4).
- Y is **Acetone** (formed from ketamine by hydrolysis with H3O+).