`C_2H_5CNoverset(HNO_(2))toAoverset(PCl_(5))toBoverset(NH_(3))toC` end product in the given sequence is

Options

A. `C_2H_5CN`
B. `CH_3NH_2`
C. `C_2H_5NH_2`
D. `CH_3CONH_2`

Answer

To solve the problem step by step, we will analyze the reactions that occur sequentially with the compound \( C_2H_5CN \).

### Step 1: Reaction with HNO₂
The first step involves the reaction of \( C_2H_5CN \) (ethyl cyanide) with \( HNO_2 \) (nitrous acid).

**Reaction:**
\[ C_2H_5CN + HNO_2 \rightarrow C_2H_5OH + N_2 + HCl \]

**Product A:**
The product formed in this reaction is \( C_2H_5OH \) (ethanol).

### Step 2: Reaction with PCl₅
Next, we take the product \( C_2H_5OH \) and react it with \( PCl_5 \) (phosphorus pentachloride).

**Reaction:**
\[ C_2H_5OH + PCl_5 \rightarrow C_2H_5Cl + POCl_3 + HCl \]

**Product B:**
The product formed here is \( C_2H_5Cl \) (ethyl chloride).

### Step 3: Reaction with NH₃
Finally, we take \( C_2H_5Cl \) and react it with \( NH_3 \) (ammonia).

**Reaction:**
\[ C_2H_5Cl + NH_3 \rightarrow C_2H_5NH_2 + HCl \]

**Product C:**
The product formed in this reaction is \( C_2H_5NH_2 \) (ethylamine).

### Conclusion
The end product \( C \) in the given sequence of reactions is \( C_2H_5NH_2 \).

### Final Answer:
The end product in the given sequence is \( C_2H_5NH_2 \).

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