`R-NH_(2)+underset("excess")(CH_(3)COCl)toA`.
The product (A) Will be

Options

A. `RNHCOCH_(3)`
B. `RN(COCH_(3))_(2)`
C. `RN(COCH_(3))_(3)Cl^(-)`
D. `R-CONH_(2)`

Answer

To solve the reaction between a primary amine (R-NH₂) and acyl chloride (CH₃COCl), we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- R-NH₂ (a primary amine)
- CH₃COCl (acetyl chloride or acyl chloride)

### Step 2: Understand the Reaction Mechanism
The primary amine (R-NH₂) will act as a nucleophile. The nitrogen atom in the amine has a lone pair of electrons that will attack the carbonyl carbon of the acyl chloride (CH₃COCl).

### Step 3: Nucleophilic Attack
The nucleophilic attack occurs as follows:
- The lone pair of electrons on the nitrogen atom attacks the carbon atom of the carbonyl group in the acyl chloride, forming a tetrahedral intermediate.

### Step 4: Formation of the Intermediate
The tetrahedral intermediate can be represented as:
- CH₃C(OH)(NH₂R)Cl (where the nitrogen is bonded to the carbon and the chlorine is still attached).

### Step 5: Deprotonation
The intermediate undergoes deprotonation (loss of a proton) from the nitrogen atom, which leads to the formation of a more stable structure.

### Step 6: Elimination of Chloride Ion
The final step involves the elimination of the chloride ion (Cl⁻) from the intermediate, leading to the formation of a secondary amide:
- CH₃C(=O)NHR (where R is the alkyl group from the primary amine).

### Step 7: Final Product
The final product (A) is:
- CH₃C(=O)NHR, which is a secondary amide.

### Conclusion
Thus, the product (A) formed from the reaction of R-NH₂ and CH₃COCl is a secondary amide, specifically R-NH-CO-CH₃.