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Write the structure of alanine at pH = 2...

Write the structure of alanine at pH = 2 and pH = 10.

A

`NH_(2)-overset(CH_(3))overset(|)(CH)-COO^(-),H_(2)overset(+)N-overset(CH_(3))overset(|)(CH)-COOH`

B

`H_(2)overset+N-overset(CH_(3))overset(|)(CH)-COO^(-),H_(2)overset(+)N-overset(CH_(3))overset(|)(CH)-COOH`

C

`H_(3)overset+N-overset(CH_(3))overset(|)(CH)-COOH,NH_(2)-overset(CH_(3))overset(|)(CH)-COO^(-)`

D

`NH_(2)-overset(CH_(3))overset(|)(CH)-COO^(-),H_(2)overset(+)N-overset(CH_(3))overset(|)(CH)-COO`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the structure of alanine at pH = 2 and pH = 10, we need to consider the behavior of alanine in acidic and basic conditions. ### Step 1: Understand the Structure of Alanine Alanine (C3H7NO2) is an amino acid with the following structure: - Amino group (NH2) - A central carbon (C) - A carboxylic acid group (COOH) - A methyl group (CH3) The structure can be represented as: ``` NH2 | CH3-C-COOH ``` ### Step 2: Analyze the Structure at pH = 2 At pH = 2, the environment is acidic. In this condition, the amino group (NH2) can accept a proton (H+), becoming positively charged (NH3+). The carboxylic acid group (COOH) remains protonated and does not lose its hydrogen. The structure of alanine at pH = 2 is: ``` NH3+ | CH3-C-COOH ``` ### Step 3: Analyze the Structure at pH = 10 At pH = 10, the environment is basic. In this condition, the carboxylic acid group (COOH) can lose a proton (H+), becoming negatively charged (COO-). The amino group (NH2) remains unchanged as it does not accept a proton in this basic environment. The structure of alanine at pH = 10 is: ``` NH2 | CH3-C-COO- ``` ### Summary of Structures: - At **pH = 2**: Alanine exists as a cation (NH3+). - At **pH = 10**: Alanine exists as an anion (COO-). ### Final Structures: 1. **At pH = 2**: ``` NH3+ | CH3-C-COOH ``` 2. **At pH = 10**: ``` NH2 | CH3-C-COO- ```
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