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30cm^(3) of a gas at 2.02 atm and 25^(@)...

`30cm^(3)` of a gas at 2.02 atm and `25^(@)C` was compressed to `15cm^(3)" at "35^(@)C.` Calculate the final pressure of the gas.

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To solve the problem step by step, we will use the combined gas law, which relates the pressure, volume, and temperature of a gas. The combined gas law is given by the formula: \[ \frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2} \] ### Step 1: Identify the given values - Initial volume, \( V_1 = 30 \, \text{cm}^3 \) ...
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