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The volume of a gas X and chlorine diffu...

The volume of a gas X and chlorine diffusing during the same time are 35 mL and 29 mL respectively. If molecular mass of chlorine is 71, calculate the molecular mass of gas X.

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`(r(O_3))/(r(Cl_2))=sqrt ((M(Cl_2))/(M(O_3))`
Rate of diffusion in sam time is proportional to volume diffuese so
`(V(O_3))/(V(Cl_2))=sqrt((M(Cl_2))/(M(O_3)))`
`35/29= sqrt((71)/(M(O_3)))rArr (35)^2/(29)^2=71/(M(O_3)) rArr M(O_3)=48.74 `
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