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A fluoride of phosphorous in gaseous sta...

A fluoride of phosphorous in gaseous state was found to diffuse 2.12 times more slowly than nitrogen under similar conditions. Calculate the molecular mass and molecular formula of this fluoride which contains one atom of phosphorous per molecule.

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To solve the problem, we need to find the molecular mass and molecular formula of a fluoride of phosphorus that diffuses 2.12 times more slowly than nitrogen. Here’s a step-by-step solution: ### Step 1: Understand the relationship between diffusion rates and molar mass According to Graham's law of effusion, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. This can be expressed as: \[ \frac{R_{\text{fluoride}}}{R_{\text{nitrogen}}} = \sqrt{\frac{M_{\text{N2}}}{M_{\text{fluoride}}}} \] ...
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