Rate of diffusion of gas A is `(1)/(2)` that of gas 'B'. If molecular mass of gas A is 16 than calculate molecular mass of gas 'B'.

Explanation

To solve the problem, we will use Graham's law of effusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.

### Step-by-Step Solution:

1. **Understand the relationship given by Graham's Law**:
\[ \frac{R_A}{R_B} = \sqrt{\frac{M_B}{M_A}} \]
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