The species having bond order same as that of
(a) CO
(b) `O_2`
(c)`N_2`
(d) `H_2`

Options

A. (a) and(b)
B. (a) and(d)
C. (c) and(d)
D. (a), (b) and(d)

Answer

To determine the species that have the same bond order as CO, O2, N2, and H2, we first need to calculate the bond order for each of these molecules.

### Step 1: Calculate the bond order of CO
1. **Count the total number of electrons**: Carbon (C) has 6 electrons, and Oxygen (O) has 8 electrons, giving a total of 14 electrons.
2. **Construct the molecular orbital (MO) configuration**:
- σ1s² σ*1s² σ2s² σ*2s² σ2p_z² (bonding)
- π2p_x², π2p_y² (bonding)
- π*2p_x¹, π*2p_y¹ (antibonding)
3. **Calculate bond order**:
- Bonding electrons = 10 (2 from σ1s, 2 from σ2s, 2 from σ2p_z, 2 from π2p_x, 2 from π2p_y)
- Antibonding electrons = 4 (2 from σ*1s, 2 from σ*2s)
- Bond order = (Bonding - Antibonding) / 2 = (10 - 4) / 2 = 3.

### Step 2: Calculate the bond order of O2
1. **Count the total number of electrons**: Oxygen (O) has 8 electrons, so O2 has 16 electrons.
2. **Construct the MO configuration**:
- σ1s² σ*1s² σ2s² σ*2s² σ2p_z² (bonding)
- π2p_x², π2p_y² (bonding)
- π*2p_x¹, π*2p_y¹ (antibonding)
3. **Calculate bond order**:
- Bonding electrons = 10 (same as above)
- Antibonding electrons = 6 (2 from σ*1s, 2 from σ*2s, 2 from π*2p_x and π*2p_y)
- Bond order = (10 - 6) / 2 = 2.

### Step 3: Calculate the bond order of N2
1. **Count the total number of electrons**: Nitrogen (N) has 7 electrons, so N2 has 14 electrons.
2. **Construct the MO configuration**:
- σ1s² σ*1s² σ2s² σ*2s² σ2p_z² (bonding)
- π2p_x², π2p_y² (bonding)
3. **Calculate bond order**:
- Bonding electrons = 10 (same as above)
- Antibonding electrons = 4 (2 from σ*1s, 2 from σ*2s)
- Bond order = (10 - 4) / 2 = 3.

### Step 4: Calculate the bond order of H2
1. **Count the total number of electrons**: Hydrogen (H) has 1 electron, so H2 has 2 electrons.
2. **Construct the MO configuration**:
- σ1s² (bonding)
3. **Calculate bond order**:
- Bonding electrons = 2 (from σ1s)
- Antibonding electrons = 0
- Bond order = (2 - 0) / 2 = 1.

### Conclusion
- **Bond order of CO = 3**
- **Bond order of O2 = 2**
- **Bond order of N2 = 3**
- **Bond order of H2 = 1**

### Final Answer
The species having the same bond order as CO (3) are:
- (a) CO
- (c) N2