The temperature, at which the volume of a given gas at 25°C becomes thrice when pressure of the system is kept constant

Options

A. 75°C
B. 894 K
C. 440°C
D. 350 K

Answer

To solve the problem, we will use Charles's Law, which states that the volume of a gas is directly proportional to its absolute temperature (in Kelvin) when the pressure is kept constant.

### Step-by-Step Solution:

1. **Understand the Given Information**:
- Initial temperature (T1) = 25°C
- Final volume (V2) = 3 times the initial volume (V1)
- Pressure is constant.

2. **Convert Initial Temperature to Kelvin**:
- To convert Celsius to Kelvin, use the formula:
\[ T(K) = T(°C) + 273 \]
- Therefore,
\[ T1 = 25 + 273 = 298 \text{ K} \]

3. **Set Up Charles's Law**:
- According to Charles's Law:
\[ \frac{V1}{V2} = \frac{T1}{T2} \]
- Here, since V2 = 3V1, we can substitute:
\[ \frac{V1}{3V1} = \frac{T1}{T2} \]
- This simplifies to:
\[ \frac{1}{3} = \frac{T1}{T2} \]

4. **Rearranging the Equation**:
- Rearranging gives:
\[ T2 = 3 \times T1 \]

5. **Substituting the Value of T1**:
- Now substitute T1 = 298 K:
\[ T2 = 3 \times 298 = 894 \text{ K} \]

6. **Final Answer**:
- The final temperature (T2) at which the volume becomes thrice is:
\[ T2 = 894 \text{ K} \]

### Summary:
The temperature at which the volume of a given gas at 25°C becomes thrice when the pressure of the system is kept constant is **894 K**.