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Which of the following pairs of gases wi...

Which of the following pairs of gases will have identical rate of effusion under similar conditions?

A

Dideuterium and Helium

B

Diprotium and Dideuterium

C

Propene and Propane

D

Nitrogen dioxide and Carbon dioxide

Text Solution

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The correct Answer is:
To determine which pair of gases will have identical rates of effusion under similar conditions, we can use Graham's law of effusion. According to Graham's law, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Therefore, for two gases to have the same rate of effusion, their molar masses must be identical. ### Step-by-Step Solution: 1. **Identify the Gases and Their Molar Masses**: - **Deuterium (D2)**: The molar mass of deuterium (D) is approximately 2 g/mol. Thus, for D2, it is \(2 \times 2 = 4 \, \text{g/mol}\). - **Helium (He)**: The molar mass of helium is approximately 4 g/mol. - **Diprotein (H2)**: The molar mass of hydrogen (H) is approximately 1 g/mol. Thus, for H2, it is \(2 \times 1 = 2 \, \text{g/mol}\). - **Diduterium (D2)**: As calculated earlier, D2 is 4 g/mol. - **Propene (C3H6)**: The molar mass is calculated as \( (12 \times 3) + (1 \times 6) = 36 + 6 = 42 \, \text{g/mol}\). - **Propane (C3H8)**: The molar mass is calculated as \( (12 \times 3) + (1 \times 8) = 36 + 8 = 44 \, \text{g/mol}\). - **Nitrogen Dioxide (NO2)**: The molar mass is calculated as \(14 + (16 \times 2) = 14 + 32 = 46 \, \text{g/mol}\). - **Carbon Dioxide (CO2)**: The molar mass is calculated as \(12 + (16 \times 2) = 12 + 32 = 44 \, \text{g/mol}\). 2. **Compare Molar Masses**: - **Pair 1**: Deuterium (4 g/mol) and Helium (4 g/mol) → Identical molar masses. - **Pair 2**: Diprotein (2 g/mol) and Diduterium (4 g/mol) → Different molar masses. - **Pair 3**: Propene (42 g/mol) and Propane (44 g/mol) → Different molar masses. - **Pair 4**: Nitrogen Dioxide (46 g/mol) and Carbon Dioxide (44 g/mol) → Different molar masses. 3. **Conclusion**: The only pair of gases with identical molar masses is Deuterium and Helium. Therefore, they will have identical rates of effusion under similar conditions. ### Final Answer: The pair of gases that will have identical rates of effusion under similar conditions is **Deuterium (D2) and Helium (He)**. ---
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