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The two ions A^+' and 'B^- have radii 85...

The two ions `A^+' and 'B^-` have radii 85 and 200 pm respectively. In the closed packed crystal of compound AB, the coordination number of `A^+` ion is

A

3

B

4

C

6

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To determine the coordination number of the `A^+` ion in the closed packed crystal of compound `AB`, we can follow these steps: ### Step 1: Identify the radii of the ions. - The radius of the cation `A^+` is given as 85 pm. - The radius of the anion `B^-` is given as 200 pm. ### Step 2: Calculate the radius ratio. - The radius ratio (r) is calculated using the formula: \[ r = \frac{\text{Radius of cation}}{\text{Radius of anion}} = \frac{85 \text{ pm}}{200 \text{ pm}} \] - Performing the calculation: \[ r = \frac{85}{200} = 0.425 \] ### Step 3: Determine the coordination number based on the radius ratio. - The radius ratio of 0.425 falls within the range of 0.414 to 0.732. - According to the radius ratio rules for coordination numbers: - A radius ratio between 0.414 and 0.732 typically corresponds to a coordination number of 6. ### Step 4: Conclusion. - Therefore, the coordination number of the `A^+` ion in the closed packed crystal of compound `AB` is 6. ### Final Answer: The coordination number of `A^+` ion is **6**. ---
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Knowledge Check

  • In the radii of A^(+) and B^(-) are 95 pm and 181 pm respectively, then the coordination number of A^(+) will be:

    A
    12
    B
    8
    C
    6
    D
    4

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