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Calculate the time to deposit 1.27 g of copper at cathode when a current of 2A was passed through the solution of `CuSO_(4)`.
`("Molar mass of "Cu=63.5g mol^(-1), 1F =96500 C mol^(-1)).`

A

`(-d[NH_4NO_2])/(dt)=k`

B

`(-d[NH_4NO_2])/(dt)=k [NH_4NO_2]`

C

`(-d[NH_4NO_2])/(dt)=k [NH_4NO_2]^(-1)`

D

`(-d[NH_4NO_2])/(dt)=k [NH_4NO_2]^2`

Text Solution

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The correct Answer is:
B
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