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The strength of "20 volume" H(2)O(2) is ...

The strength of "20 volume" `H_(2)O_(2)` is equal to

A

`0.03%`

B

`6%`

C

`0.2%`

D

0.15

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The correct Answer is:
B
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Calculate the strenght of 5 volumes H_(2)O_(2) solution.

What will be the strength of 20 vol of H_(2)O_(2) in terms of gram per litre?

The strength of H_(2)O_(2) is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of H_(2)O_(2) on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of H_(2)O_(2) gives 10 litre of O_(2) at 1 atm and 273 K The decomposition of H_(2)O_(2) is shown as under : H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g) H_(2)O_(2) can acts as oxidising as well as reducing agent. As oxidizing agent H_(2)O_(2) is converted into H_(2)O and as reducing agent H_(2)O_(2) is converted into O_(2) . For both cases its n-factor is 2. :. "Normality " "of" H_(2)O_(2) "solution" =2xx "molarity of" H_(2)O_(2) solution 20mL of H_(2)O_(2) solution is reacted with 80 mL of 0.05 MKMnO_(4) "in acidic medium then what is the volume strength of" H_(2)O_(2) ?

The strength of H_(2)O_(2) is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of H_(2)O_(2) on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of H_(2)O_(2) gives 10 litre of O_(2) at 1 atm and 273 K The decomposition of H_(2)O_(2) is shown as under : H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g) H_(2)O_(2) can acts as oxidising as well as reducing agent. As oxidizing agent H_(2)O_(2) is converted into H_(2)O and as reducing agent H_(2)O_(2) is converted into O_(2) . For both cases its n-factor is 2. :. "Normality " " of " H_(2)O_(2) solution =2xx "molarity of" H_(2)O_(2) solution What is thepercentage strength (%w/V) of "11.2 V" H_(2)O_(2)

The strength of H_(2)O_(2) is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of H_(2)O_(2) on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of H_(2)O_(2) gives 10 litre of O_(2) at 1 atm and 273 K The decomposition of H_(2)O_(2) is shown as under : H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g) H_(2)O_(2) can acts as oxidising as well as reducing agent. As oxidizing agent H_(2)O_(2) is converted into H_(2)O and as reducing agent H_(2)O_(2) is converted into O_(2) . For both cases its n-factor is 2. :. "Normality " "of" H_(2)O_(2) " solution " =2xx " molarity of" H_(2)O_(2) solution What is the molarity of "11.2 V" H_(2)O_(2) ?

The strength of H_(2)O_(2) is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of H_(2)O_(2) on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of H_(2)O_(2) gives 10 litre of O_(2) at 1 atm and 273 K The decomposition of H_(2)O_(2) is shown as under : H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g) H_(2)O_(2) can acts as oxidising as well as reducing agent. As oxidizing agent H_(2)O_(2) is converted into H_(2)O and as reducing agent H_(2)O_(2) is converted into O_(2) . For both cases its n-factor is 2. :. "Normality " "of" H_(2)O_(2) " solution " =2xx "molarity of" H_(2)O_(2) solution 40 g Ba(MnO_(4))_(2) (mol.mass=375) sample containing some inert impurities in acidic medium completely reacts with 125 mL of "33.6 V" of H_(2)O_(2) . What is the percentage purity of the sample ?

The strength of 11.2 volume solution of H_(2)O_(2) is: [Given that molar mass of H = 1 g mol^(-1) and O = 16 g mol^(-1) ]

The volume strength of 10 NH_(2)O_(2) is :

the percentage strength of 10 volume H_2 O_2 solution is nearly

The strength of H_(2)O_(2) is expressed in many ways like molarity , normality , % strength and volume strengths But out of all these form of strengths , volume strength has great significance for chemical reactions . This decomposition of H_(2)O_(2) is shown as under H_(2)O_(2)(l) to H_(2)O(l) + (1)/(2)O_(2)(g) 'x' volume strength of H_(2)O_(2) means one volume (litre or ml) of H_(2)O_(2) releases x volume (litre or ml) of O_(2) at NTP . 1 litre H_(2)O_(2) release x litre of O_(2) at NTP =(x)/(22.4) moles of O_(2) From the equation , 1 mole of O_(2) produces from 2 moles of H_(2)O_(2) . (x)/(22.4) moles of O_(2) produces from 2xx(x)/(22.4) moles of H_(2)O_(2) =(x)/(11.2) moles of H_(2)O_(2) So, molarity of H_(2)O_(2)=((x)/(11.2))/(1)=(x)/(11.2)M Normality =n-factor xx molarity =2xx(x)/(11.2)=(x)/(5.6) N What is the percentage strength of "15 volume" H_(2)O_(2) ?

AAKASH INSTITUTE ENGLISH-MOCK TEST 22-Example
  1. Hydrogen gas reduces which metal ion in its aqueous solution?

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  2. Hydrogen acts as a reducing agent and thus resembles

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  3. In which of the compounds, the oxidation state of hydrogen is -1

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  4. An element reacts with hydrogen to form a compound X which on treatmen...

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  5. High purity dihydrogen is obtained by electrolysing

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  6. Only temporary hardness of water is removed by

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  7. In Clark's method the chemical used to remove hardness of water is

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  8. Heavy water is

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  9. The incorrect statement about the structure of H2O2 is

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  10. The strength of "20 volume" H(2)O(2) is equal to

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  11. Which of the following elements combines directly with nitrogen to for...

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  12. The correct order of hydration enthalpies of alkali metal ions is:

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  13. The colour given to the flame by sodium salt is

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  14. The following pair that cannot exist in solution is

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  15. When NaOH is prepared in Castner-Kellner cell,the gas evolved at the a...

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  16. which of the following statements is/are incorrect?

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  17. Which of the following are thermodynamically stable?

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  18. Which is incorrect statement about lithium and magnesium?

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  19. Solvay's process is used for the manufacture of

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  20. What is formed when calcium carbide reacts with heavy water?

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