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Laboratory method for the preperation of...

Laboratory method for the preperation of diborane involves the oxidation of

A

Sodium borohydride with iodine

B

Sodium borohydride with fluorine

C

Sodium borohydride with chlorine

D

Sodium borohydride with 'KMnO_4'

Text Solution

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The correct Answer is:
To solve the question regarding the laboratory method for the preparation of diborane, we need to identify the correct oxidation reaction involving sodium borohydride. Here’s a step-by-step solution: ### Step 1: Understand the Components We need to identify the reactants involved in the preparation of diborane. The main reactant mentioned is sodium borohydride (NaBH4). **Hint:** Look for the oxidation reactions involving sodium borohydride. ### Step 2: Identify the Oxidizing Agent The question provides several options for the oxidizing agent that can react with sodium borohydride. The options are: - A. Iodine (I2) - B. Fluorine (F2) - C. Chlorine (Cl2) - D. Potassium permanganate (KMnO4) **Hint:** Consider which of these oxidizing agents is commonly used in laboratory settings for oxidation reactions. ### Step 3: Determine the Correct Reaction The correct laboratory method for the preparation of diborane involves the oxidation of sodium borohydride with iodine. The reaction can be written as: \[ 2 \text{NaBH}_4 + \text{I}_2 \rightarrow \text{B}_2\text{H}_6 + 2 \text{NaI} + \text{H}_2 \] **Hint:** Focus on the stoichiometry of the reaction and the products formed. ### Step 4: Analyze the Products From the reaction, we can see that diborane (B2H6) is formed along with sodium iodide (NaI) and hydrogen gas (H2). This confirms that the reaction is indeed producing diborane. **Hint:** Check if the products align with the expected outcome of the oxidation process. ### Conclusion The correct answer to the question is: **A. sodium borohydride with iodine.** ### Summary of Steps: 1. Identify the reactant (sodium borohydride). 2. Analyze the oxidizing agents provided. 3. Determine the correct reaction involving sodium borohydride and iodine. 4. Confirm the products formed in the reaction.
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