High spin complex of d^6 configuration i...

High spin complex of `d^6` configuration in an octahedral field will have the CFSE equal to

`(-12)/5 triangle_circ`

`(-14)/5 triangle_circ`

`(-41)/5 triangle_circ`

`(-2)/5 triangle_circ`

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Low spin complex of d^6 -cation in an octahedral field will have the following energy:

Crystal field stabilization energy of high spin complex cation having d_5 configuration in an octahedral field is

d^(6) configuration will result in total spin of :

Which of the following is the correct electronic configuration in octahedral complex with d^4 configuration?

The total spin resulting from a d^7 configuration is :

The total spin resulting from d^(9) configuration is

For a d^4 metal ion in an octahedral field, the correct electronic configuration is :

When degenerate d-orbitals of an isolated atom/ion come under influence of magnetic field of ligands, the degeneray is lost. The two set t_(2g)(d_(xy),d_(yz),d_(xz)) and e_(g) (d_(x^(2))-d_(x^(2)-y^(2)) are either stabilized or destabilized depending upon the nature of magnetic field. it can be expressed diagrammatically as: Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for tetrahedral complexes, Delta is about 4/9 times to Delta_(0) (CFSE for octahedral complex). this energy lies in visible region and i.e., why electronic transition are responsible for colour. such transition are not possible with d^(0) and d^(10) configuration. Q. For an octahedral complex, which of the followin d-electron configuration will give maximum CFSE?

On the basis of crystal field theory. Write the electronic confirguration of d^(6) in terms of t_(2g) " and " e_(g) in an octahedral field when D_(0) lt P.

AAKASH INSTITUTE ENGLISH-Mock test 27-EXAMPLE

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