Among the following halide ions `(X^-)` reaction, which is feasible is?

Answer

To determine which halide ion reaction is feasible, we will analyze each reaction step by step.

### Step 1: Analyze the First Reaction
- **Reaction**: Halide ion (X^-) with an alkane.
- **Explanation**: In this case, the halide ion acts as a nucleophile. However, alkanes are non-polar and do not have a significant positive charge to attract the nucleophile. Therefore, this reaction is not feasible.

### Step 2: Analyze the Second Reaction
- **Reaction**: Halide ion (X^-) with ethane.
- **Explanation**: Similar to the first reaction, ethane is also a non-polar molecule. The carbon-hydrogen bonds do not provide a suitable site for nucleophilic attack. Hence, this reaction is also not feasible.

### Step 3: Analyze the Third Reaction
- **Reaction**: Halide ion (X^-) with methyl alcohol (methanol).
- **Explanation**: In this case, methanol contains a hydroxyl group (OH), which can act as a nucleophile. When the halide ion reacts with methanol, it can lead to a nucleophilic substitution reaction. The hydroxyl group can be replaced by the halide ion, resulting in the formation of alkyl halides and water. This reaction is feasible, especially when heated with hydrogen halides (HCl or HBr).

### Conclusion
- Among the given reactions, only the reaction of the halide ion with methyl alcohol is feasible.

### Final Answer
The feasible reaction is the one between the halide ion (X^-) and methyl alcohol.

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