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Which of the following is not planar in ...

Which of the following is not planar in structure?

A

`CH_2=CH-CH=CH_2`

B

`CH_2=CH-CN`

C

`CH_2=C=CH_2`

D

`CH_2=C=C=CH_2`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given structures is not planar, we need to analyze the hybridization of the carbon atoms in each option. The key points to remember are: 1. **Hybridization Types**: - **sp Hybridization**: Linear structure, bond angle of 180°. - **sp² Hybridization**: Planar structure, bond angle of 120°. - **sp³ Hybridization**: Non-planar (tetrahedral), bond angle of approximately 109.5°. 2. **Planarity Considerations**: - Molecules with only sp² or sp hybridized carbons are generally planar. - Molecules with sp³ hybridized carbons are non-planar. - Even with sp² hybridized carbons, steric effects and pi-pi interactions can lead to non-planarity. ### Step-by-Step Solution: 1. **Identify the Hybridization of Each Carbon**: - For each option, determine the hybridization of the carbon atoms based on the number of bonds (single, double, triple) they form. 2. **Evaluate Each Option**: - **Option 1**: CH₃-CH₂-CH₃ (Propane) - All carbons are sp³ hybridized (3 sp³ carbons). - **Conclusion**: Non-planar. - **Option 2**: CH₂=CH-CH=CH₂ (Butadiene) - All carbons are sp² hybridized (4 sp² carbons). - **Conclusion**: Planar. - **Option 3**: CH₂=CH-CH=CH₂ (Allene) - The first and last carbons are sp² hybridized, and the middle carbon is sp hybridized. - Due to pi-pi interactions, the structure is non-planar. - **Conclusion**: Non-planar. - **Option 4**: CH₂=CH-CH₂ (Vinyl group) - All carbons are sp² hybridized. - **Conclusion**: Planar. 3. **Final Decision**: - Among the options, the structure that is not planar is **Option 3** (Allene). ### Answer: **Option 3** is not planar in structure.
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Knowledge Check

  • Which of the following is planar?

    A
    `SiCl_4`
    B
    `NF_3`
    C
    `SF_4`
    D
    `XeF_4`
  • Which of the following is not a planar molecule?

    A
    `H_(2)C=C=CH_(2)`
    B
    `H_(2)C=C=CH_(2)`
    C
    `H_(2)C=C=O`
    D
    `NC-HC=CH-CN`
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