which of the following compound will show stereo isomerism?

Options

A. 3-Pentarol
B. 3-Pentanone
C. But-2-ene
D. Propane

Answer

To determine which of the given compounds will show stereoisomerism, we will analyze each compound based on the presence of double bonds and the requirement for stereoisomerism.

### Step-by-Step Solution:

1. **Identify the Compounds**:
- We have the following compounds to analyze:
- 3-Pentanol
- 3-Pentanone
- But-2-ene
- Propane

2. **Analyze 3-Pentanol**:
- Structure: CH3-CH2-CH(OH)-CH2-CH3
- This compound has a hydroxyl (-OH) group but does not contain any double bonds.
- **Conclusion**: 3-Pentanol does not show stereoisomerism.

3. **Analyze 3-Pentanone**:
- Structure: CH3-CH2-CO-CH2-CH3
- This compound has a carbonyl (C=O) group but does not have a double bond between carbon atoms.
- **Conclusion**: 3-Pentanone does not show stereoisomerism.

4. **Analyze But-2-ene**:
- Structure: CH3-CH=CH-CH3
- This compound has a double bond between two carbon atoms.
- For stereoisomerism to occur, the carbon atoms involved in the double bond must have different substituents.
- In But-2-ene, the two carbon atoms of the double bond have different groups attached (methyl and hydrogen).
- **Conclusion**: But-2-ene shows stereoisomerism.

5. **Analyze Propane**:
- Structure: CH3-CH2-CH3
- This compound is a simple alkane with no double bonds.
- **Conclusion**: Propane does not show stereoisomerism.

### Final Conclusion:
Among the compounds analyzed, **But-2-ene** is the only compound that shows stereoisomerism due to the presence of a double bond between carbon atoms with different substituents.

---