An alkane, A on ozonolysis gives two products propanal and propanone. Which of the given statements is incorrect for A?

Options

A. Compound A is pent-2-ene
B. Compound A on hydrogenation gives 2-methyl pentane
C. Compound A can undergo bromination reaction
D. Compound a forms 2-bromo, 2-methylpentane on treating with HBr

Answer

To solve the question regarding the alkane A that gives propanal and propanone upon ozonolysis, we will follow these steps:

### Step 1: Understand Ozonolysis
Ozonolysis is a reaction where alkenes are cleaved by ozone (O3) to form carbonyl compounds (aldehydes and ketones). In this case, we know that the products are propanal (an aldehyde) and propanone (a ketone).

### Step 2: Identify the Structure of Alkane A
Since ozonolysis produces two products, we need to determine the structure of alkene A that could lead to propanal and propanone.

- Propanal (CH3CHO) has the structure with a carbonyl group (C=O) at the end of the carbon chain.
- Propanone (CH3COCH3) has a carbonyl group in the middle of the carbon chain.

### Step 3: Determine the Possible Alkene
To produce both propanal and propanone, alkene A must have a double bond that, when cleaved, can yield these two products.

A suitable structure for alkene A can be 2-methylpent-2-ene (CH3C(CH3)=C(CH3)CH2CH3). When ozonolysis occurs, the double bond between the second and third carbon atoms will break, leading to the formation of:

- Propanal from the terminal carbon (CH3CH2CHO)
- Propanone from the central carbon (CH3COCH3)

### Step 4: Analyze the Statements
Now, we need to evaluate the statements given in the question to find the incorrect one regarding alkene A.

1. **Statement about the IUPAC name**: If the compound is named incorrectly as pent-2-ene instead of 2-methylpent-2-ene, this would be incorrect.
2. **Statement about hydrogenation**: Hydrogenation of alkene A would yield 2-methylpentane, which is correct.
3. **Statement about bromination**: The compound undergoing bromination to form 2-bromo-2-methylpentane is also correct.

### Conclusion
The incorrect statement regarding alkene A is that it is named simply as pent-2-ene, which is misleading since the correct IUPAC name should be 2-methylpent-2-ene.

### Final Answer
The incorrect statement for alkane A is that it is named as pent-2-ene.

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