IUPAC Name of K2[PdCl4]

Answer

To determine the IUPAC name of the compound K2[PdCl4], we can follow these steps:

### Step 1: Identify the components of the complex
The compound K2[PdCl4] consists of:
- Potassium (K)
- Palladium (Pd)
- Chlorine (Cl)

### Step 2: Determine the oxidation state of Palladium
In the complex [PdCl4]²⁻, each chlorine (Cl) has a charge of -1. Since there are 4 chlorine atoms, the total negative charge contributed by chlorine is -4. To balance this charge in the complex, palladium must have an oxidation state of +2. Therefore, the oxidation state of palladium (Pd) in this complex is +2.

### Step 3: Name the ligands
The ligands in this complex are:
- Chlorine (Cl), which is named "chloro" in the IUPAC nomenclature. Since there are 4 chlorine atoms, we use the prefix "tetra-" to indicate four ligands. In coordination chemistry, "chloro" can also be referred to as "chlorido."

### Step 4: Name the metal
The metal palladium (Pd) is named "palladate" when it is in a coordination complex. Since we have determined that palladium has an oxidation state of +2, we will indicate this in the name.

### Step 5: Combine the names
The IUPAC name is constructed by placing the cation name first followed by the anion name. In this case:
- The cation is potassium (K), and since there are two potassium ions, we simply use "potassium."
- The anion part is "tetrachloropalladate(II)" indicating the presence of four chlorido ligands and the +2 oxidation state of palladium.

### Final IUPAC Name
Putting it all together, the IUPAC name of K2[PdCl4] is **potassium tetrachloropalladate(II)**.

---