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The following reaction takes place throu...

The following reaction takes place through `CH_3-O-CH_2-CH_3 + HI` to `CH_3-I + CH_3-CH_2-OH`

A

`S_N1` mechanism

B

`S_N2` mechanism

C

`S_N1` in first step and E2 in second step

D

`S_N2` in first step and E1 in second step

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The correct Answer is:
To determine the mechanism of the reaction between CH₃-O-CH₂-CH₃ (ethyl methyl ether) and HI (hydroiodic acid) to form CH₃-I (methyl iodide) and CH₃-CH₂-OH (ethanol), we will analyze the steps involved in the reaction. ### Step-by-Step Solution: 1. **Identify the Reactants and Products:** - Reactants: CH₃-O-CH₂-CH₃ + HI - Products: CH₃-I + CH₃-CH₂-OH 2. **Protonation of the Ether:** - The ether (CH₃-O-CH₂-CH₃) reacts with HI. The oxygen atom in the ether has lone pairs and can donate one of these lone pairs to the hydrogen ion (H⁺) from HI, resulting in the protonation of the ether. - This leads to the formation of a protonated ether (CH₃-O⁺-CH₂-CH₃). 3. **Formation of the Leaving Group:** - The protonated ether is now more reactive. The bond between the oxygen and the CH₂ group becomes weaker due to the positive charge on the oxygen. This allows the CH₂ group to leave as a carbocation (CH₃-O⁺-CH₂⁺) and I⁻ (iodide ion) to be released. 4. **Nucleophilic Attack:** - The iodide ion (I⁻), which is a good nucleophile, can now attack the carbocation formed in the previous step. This attack occurs at the carbon atom that was previously bonded to the leaving group (CH₂). - The nucleophilic attack by I⁻ results in the formation of CH₃-I (methyl iodide). 5. **Formation of Ethanol:** - The remaining part of the ether (CH₃-CH₂-OH) is formed as a byproduct when the ether is cleaved. 6. **Determine the Mechanism:** - The reaction involves the formation of a carbocation intermediate and a nucleophilic attack by I⁻, which indicates that the mechanism is bimolecular nucleophilic substitution (SN2). The nucleophile attacks the substrate in a single step, leading to the formation of products. ### Conclusion: The mechanism for the reaction of CH₃-O-CH₂-CH₃ with HI to form CH₃-I and CH₃-CH₂-OH is an **SN2 mechanism**.
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AAKASH INSTITUTE ENGLISH-MOCK TEST 37-Exercise
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  2. The following reaction takes place through CH3-O-CH2-CH3 + HI to CH3-I...

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  3. Which of the following is an appropriate set of reactants for the prep...

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  4. The common name of Prop-2-enal is

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  5. For denaturation of ethanol

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  6. In aldehydes and ketones

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  7. What is the molar solubility product for V3(PO4)5 in terms of K(SP)?

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  8. If ethanol and chloroform are present in a molar ratio of 2:3 then wha...

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  9. 5 moles of liquid X and 10 moles of liquid Y make a solution having a ...

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  10. When 2.0 grams of copper (II) nitrate is added to 1000 ml of pure wate...

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  11. At 70°C the vapor pressure of pure water is 31 kPa. Which of the follo...

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  12. 117 g of NaCl is added to 222 g of water in a saucepan. At what does t...

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  13. Boiling point of chloroform is 61°C. After addition of 5.0 g of a non-...

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  14. Pure CS2 melts at -112°C. 228 grams of propylene glycol crystals is mi...

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  15. Addition of water to ethyne in the presence of H2SO4 and HgSO4 gives

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  16. The given reaction is an example of

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  17. The van't Hoff factor of BaCl2 at 0.01 M concentration is 1.98. The pe...

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  18. n-Butyl bromide has higher boiling point than t-butyl bromide.

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  19. The depression of freezing point of a solution of acetic acid in benze...

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  20. The incorrect statement for aldehydes and ketones is

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