What is the EMF of a galvanic cell if E°cathode = 0.80 volts and E°anode = -0.76 volts?

Options

A. 1.56 volts
B. 0.04 volts
C. -1.56 volts
D. -0.04 volts

Answer

To find the EMF (electromotive force) of a galvanic cell, we can use the formula:

\[ E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}} \]

### Step-by-Step Solution:

1. **Identify the values given**:
- \( E^\circ_{\text{cathode}} = 0.80 \, \text{volts} \)
- \( E^\circ_{\text{anode}} = -0.76 \, \text{volts} \)

2. **Substitute the values into the formula**:
\[ E^\circ_{\text{cell}} = 0.80 \, \text{volts} - (-0.76 \, \text{volts}) \]

3. **Simplify the equation**:
- Subtracting a negative is the same as adding:
\[ E^\circ_{\text{cell}} = 0.80 \, \text{volts} + 0.76 \, \text{volts} \]

4. **Perform the addition**:
\[ E^\circ_{\text{cell}} = 1.56 \, \text{volts} \]

5. **Conclusion**:
- The EMF of the galvanic cell is \( 1.56 \, \text{volts} \).

### Final Answer:
The EMF of the galvanic cell is **1.56 volts**.

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