What is the EMF of a galvanic cell if the standard reduction potential of the reduction half-reaction is -0.38 volts and the standard reduction potential of the oxidation half-reaction is 0.52 volts?

Options

A. -0.9 volts
B. -0.6 volts
C. 0.9 volts
D. 0.6 volts

Answer

To find the EMF (Electromotive Force) of a galvanic cell, we can use the formula that relates the standard reduction potentials of the half-reactions involved. Here’s how to calculate it step by step:

### Step-by-Step Solution:

1. **Identify the Standard Reduction Potentials**:
- The standard reduction potential for the reduction half-reaction (E°_reduction) is given as -0.38 volts.
- The standard reduction potential for the oxidation half-reaction (E°_oxidation) is given as 0.52 volts.

2. **Use the EMF Formula**:
- The EMF of the galvanic cell (E°_cell) can be calculated using the formula:
\[ E°_{cell} = E°_{reduction} - E°_{oxidation} \]

3. **Substitute the Values**:
- Substitute the given values into the formula:
\[ E°_{cell} = (-0.38 \, \text{V}) - (0.52 \, \text{V}) \]

4. **Perform the Calculation**:
- Calculate the EMF:
\[ E°_{cell} = -0.38 - 0.52 = -0.90 \, \text{V} \]

5. **Conclusion**:
- The EMF of the galvanic cell is -0.90 volts.

### Final Answer:
The EMF of the galvanic cell is -0.90 volts.

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