What is the EMF of a galvanic cell if the standard oxidation potential of the oxidation half-reaction is 0.64 volts and the standard reduction potential of the reduction half-reaction is 0.48 volts?

Options

A. 1.48 volts
B. 1.12 volts
C. 1.36 volts
D. 0.96 volts

Answer

To find the EMF (Electromotive Force) of a galvanic cell, we can use the following formula:

\[ \text{EMF} = \text{SOP (Standard Oxidation Potential)} + \text{SRP (Standard Reduction Potential)} \]

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Standard Oxidation Potential (SOP) of the oxidation half-reaction: \(0.64 \, \text{V}\)
- Standard Reduction Potential (SRP) of the reduction half-reaction: \(0.48 \, \text{V}\)

2. **Write the Formula for EMF:**
\[ \text{EMF} = \text{SOP} + \text{SRP} \]

3. **Substitute the Given Values into the Formula:**
\[ \text{EMF} = 0.64 \, \text{V} + 0.48 \, \text{V} \]

4. **Perform the Addition:**
\[ \text{EMF} = 1.12 \, \text{V} \]

5. **Conclusion:**
The EMF of the galvanic cell is \(1.12 \, \text{V}\).

### Final Answer:
The EMF of the galvanic cell is \(1.12 \, \text{V}\).

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