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What is the value of rate constant k if ...

What is the value of rate constant k if the value of the activation energy Ea and the frequency factor A are 49 kJ / mol and 9 × `10^10 S^-1` respectively? (T = 313 K)

A

6 × `10^2 S^-1`

B

9 × `10^2 S^-1`

C

3 × `10^2 S^-1`

D

6 × `10^-2 S^-1`

Text Solution

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The correct Answer is:
To find the value of the rate constant \( k \) using the Arrhenius equation, we can follow these steps: ### Step 1: Write down the Arrhenius equation The Arrhenius equation relates the rate constant \( k \) to the activation energy \( E_a \), the frequency factor \( A \), and the temperature \( T \): \[ k = A e^{-\frac{E_a}{RT}} \] where: - \( k \) = rate constant - \( A \) = frequency factor - \( E_a \) = activation energy - \( R \) = universal gas constant (8.314 J/(mol·K)) - \( T \) = temperature in Kelvin ### Step 2: Convert activation energy to the correct units The activation energy \( E_a \) is given as 49 kJ/mol. We need to convert this to Joules per mole: \[ E_a = 49 \, \text{kJ/mol} = 49 \times 10^3 \, \text{J/mol} = 49000 \, \text{J/mol} \] ### Step 3: Substitute the known values into the equation Given: - \( A = 9 \times 10^{10} \, \text{s}^{-1} \) - \( R = 8.314 \, \text{J/(mol·K)} \) - \( T = 313 \, \text{K} \) Now we can substitute these values into the Arrhenius equation: \[ k = 9 \times 10^{10} \, e^{-\frac{49000}{8.314 \times 313}} \] ### Step 4: Calculate the exponent First, calculate the denominator: \[ RT = 8.314 \times 313 \approx 2600.602 \, \text{J/mol} \] Now calculate the exponent: \[ -\frac{E_a}{RT} = -\frac{49000}{2600.602} \approx -18.84 \] ### Step 5: Calculate \( e^{-\frac{E_a}{RT}} \) Now, calculate \( e^{-18.84} \): \[ e^{-18.84} \approx 1.3 \times 10^{-9} \] ### Step 6: Calculate the rate constant \( k \) Now substitute this back into the equation for \( k \): \[ k = 9 \times 10^{10} \times 1.3 \times 10^{-9} \approx 1.17 \times 10^{2} \, \text{s}^{-1} \] ### Step 7: Finalize the result Thus, the value of the rate constant \( k \) is approximately: \[ k \approx 117 \, \text{s}^{-1} \approx 1.17 \times 10^{2} \, \text{s}^{-1} \] ### Summary The value of the rate constant \( k \) is approximately \( 117 \, \text{s}^{-1} \). ---
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