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A cyclist starts from the centre O of ci...

A cyclist starts from the centre O of circular path of radius 10 m, covers the radius of circular path and reaches at point X on circumference, then cycles along the semi-circular path and reaches the point Y. If he takes 10 minutes to go from O to Y via X, then the net displacement and average speed of the cyclist would be

A

`Zero, 10 ms^(-1)`

B

`10 m, ((1+ pi)/60)ms^(-1)`

C

`10 m, ((1+ pi)/6)ms^(-1)`

D

`10 m, ((1- pi)/60)ms^(-1)`

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The correct Answer is:
To solve the problem step-by-step, we will determine the net displacement and average speed of the cyclist as described in the question. ### Step 1: Understand the Path Taken by the Cyclist The cyclist starts from the center O of a circular path with a radius of 10 m. He first travels to point X on the circumference of the circle, which is a distance equal to the radius (10 m). Then, he cycles along the semicircular path to reach point Y. ### Step 2: Calculate the Net Displacement The net displacement is the straight-line distance from the starting point O to the endpoint Y. Since Y is directly opposite to O on the circumference of the circle, the displacement is equal to the radius of the circle. - **Displacement (O to Y)** = Radius of the circle = 10 m ### Step 3: Calculate the Total Distance Traveled The total distance traveled by the cyclist consists of two parts: 1. Distance from O to X (which is the radius of the circle). 2. Distance from X to Y (which is the length of the semicircular path). - Distance OX = 10 m (radius) - For the semicircular path from X to Y: - The angle for a semicircle is π radians. - The arc length (distance from X to Y) can be calculated using the formula: \[ \text{Arc Length} = \theta \times r \] - Here, \(\theta = \pi\) and \(r = 10\) m. - Therefore, \[ \text{Arc Length} = \pi \times 10 = 10\pi \text{ m} \] - **Total Distance** = Distance OX + Arc Length XY \[ \text{Total Distance} = 10 + 10\pi \text{ m} \] ### Step 4: Calculate the Average Speed The average speed is calculated using the formula: \[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \] - The total time taken is given as 10 minutes, which we convert to seconds: \[ \text{Total Time} = 10 \times 60 = 600 \text{ seconds} \] - Now substituting the values into the average speed formula: \[ \text{Average Speed} = \frac{10 + 10\pi}{600} \] - Simplifying this gives: \[ \text{Average Speed} = \frac{10(1 + \pi)}{600} = \frac{1 + \pi}{60} \text{ m/s} \] ### Final Results - **Net Displacement** = 10 m - **Average Speed** = \(\frac{1 + \pi}{60}\) m/s
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