A particle moves on a straight line with velocity 2 m/s covers a distance of 5 m, returns back to initial position along same path with velocity 4 m/s. The distance and displacement covered by particle are respectively.

Options

A. 10 m, zero
B. Zero, 10 m
C. 5 m, 5 m
D. Zero, zero

Answer

To solve the problem, we need to determine both the distance and displacement covered by the particle as it moves along a straight line.

### Step-by-Step Solution:

1. **Initial Movement (O to P)**:
- The particle moves from point O to point P.
- Distance covered = 5 m (given).
- Since the particle moves in a straight line, the displacement is also equal to the distance in this case.
- Displacement = 5 m.

2. **Return Movement (P to O)**:
- The particle then returns from point P back to point O.
- Distance covered during this return = 5 m (again, given).
- However, since it is returning to the initial position, the displacement for this segment is negative with respect to the original direction (assuming right is positive).
- Displacement = -5 m.

3. **Total Distance Covered**:
- Total distance = Distance from O to P + Distance from P to O.
- Total distance = 5 m + 5 m = 10 m.

4. **Total Displacement**:
- Total displacement = Displacement from O to P + Displacement from P to O.
- Total displacement = 5 m + (-5 m) = 0 m.

### Final Results:
- Distance covered by the particle = 10 m.
- Displacement covered by the particle = 0 m.

### Summary:
The distance and displacement covered by the particle are respectively:
- Distance = 10 m
- Displacement = 0 m