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A particle starting from rest attains a ...

A particle starting from rest attains a velocity of `50 ms^(-1)` in 5 s. The acceleration of the particle is

A

`5 m/s^2`

B

`10 m/s^2`

C

`50 m/s^2`

D

`100 m/s^2`

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The correct Answer is:
To find the acceleration of the particle, we can use the first equation of motion, which relates initial velocity, final velocity, acceleration, and time. Here's the step-by-step solution: ### Step 1: Identify the given values - Initial velocity (u) = 0 m/s (since the particle starts from rest) - Final velocity (v) = 50 m/s - Time (t) = 5 s ### Step 2: Write down the first equation of motion The first equation of motion is: \[ v = u + at \] where: - \( v \) = final velocity - \( u \) = initial velocity - \( a \) = acceleration - \( t \) = time ### Step 3: Substitute the known values into the equation Substituting the values we have: \[ 50 = 0 + a \cdot 5 \] ### Step 4: Simplify the equation This simplifies to: \[ 50 = 5a \] ### Step 5: Solve for acceleration (a) To find \( a \), divide both sides of the equation by 5: \[ a = \frac{50}{5} \] ### Step 6: Calculate the acceleration Calculating the right side gives: \[ a = 10 \, \text{m/s}^2 \] ### Final Answer The acceleration of the particle is \( 10 \, \text{m/s}^2 \). ---
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