For an object thrown at 45^(@) to the ho...

For an object thrown at `45^(@)` to the horizontal, the maximum height H and horizontal range R are related as

R = 4H

R = 8H

R = 2H

R = H

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

Mock Test 40: PHYSICS
AAKASH INSTITUTE ENGLISH|Exercise Example|29 Videos
MOCK TEST 6
AAKASH INSTITUTE ENGLISH|Exercise Example|365 Videos

Similar Questions

Explore conceptually related problems

An object is projected at an angle of 45^(@) with the horizontal. The horizontal range and the maximum height reached will be in the ratio.

A stone projected with a velocity u at an angle (theta )with the horizontal reaches maximum heights H_(1) . When it is projected with velocity u at an angle (pi/2-theta) with the horizontal, it reaches maximum height H_(2) . The relations between the horizontal range R of the projectile, H_(1) and H_(2) , is

An object is thrown along a direction inclined at an angle of 45^(@) with the horizontal direction. The horizontal range of the object is equal to

An object is thrown along a direction inclined at an angle of 45^(@) with the horizontal direction. The horizontal range of the particle is equal to

A body is projected with velocity 'u' so that the maximum height is thrice the horizontal range. Then find the maximum height .

A body is projected with velocity 'u' so that the maximum height is thrice the horizontal range. Then the maximum height is

If a body 'A' of mass M is thrown with velocity V at an angle of 30^(@) to the horizontal and another body B of the same mass is thrown with the same speed at an angle of 60^(@) to the horizontal, the ratio of horizontal ranges of A to B will be

A ball is thrown at a speed of 40 m/s at an angle of 60^0 with the horizontal. Find a. the maximum height reached and b. the range of te ball. Take g=10 m/s^2 .

The maximum height attained by a projectile when thrown at an angle theta with the horizontal is found to be half the horizontal range. Then theta is equal to

A stone is thrown at an angle theta to the horizontal reaches a maximum height H. Then the time of flight of stone will be:

AAKASH INSTITUTE ENGLISH-MOCK TEST 5-Example

A projectile is projected from ground with initial velocity vecu=u(0)h...
Text Solution
|
Two balls are projected from two points A and B,x metre apart as shown...
Text Solution
|
For an object thrown at 45^(@) to the horizontal, the maximum height H...
Text Solution
|
If two projectile of same mass are thrown at an angle of 50° and 40° w...
Text Solution
|
Calculate the average angular velocity of the hour hand of the of a cl...
Text Solution
|
A particle with the constant speed in a circle of radius r and time pe...
Text Solution
|
An electron moves in circular orbit of radius r with constant speed v....
Text Solution
|
A particle is moving on a circular path of radius 10m with uniform spe...
Text Solution
|
A particle is moving along a circular path with uniform speed. Through...
Text Solution
|
If a particle moves in a circle describing equal angles in equal inter...
Text Solution
|
If a particle is moving on circular path with uniform speed,then which...
Text Solution
|
The degrees of freedom of CO gas molecule at moderate temperature is
Text Solution
|
7 g N2 and 8 g O2 is filled in a container of volume 5 litre at temper...
Text Solution
|
Amount of heat energy required to raise the temperature of 2 g neon ...
Text Solution
|
An open vessel at 27^oC is heated to 127^oC. The fraction of mass of a...
Text Solution
|
Tensile stress is possible in
Text Solution
|
A wire has Poisson's ratio 0.3. If the change in the length of the wir...
Text Solution
|
A wire of cross-sectional area A breaks due to its own weight when len...
Text Solution
|
If in case-A, elongation in wire of length L is l. Then for same wire,...
Text Solution
|
The height of mercury in the barometer tube is 70cm due to entrapped a...
Text Solution
|