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If two projectile of same mass are throw...

If two projectile of same mass are thrown at an angle of 50° and 40° with the horizontal with the same speed then, which of the following statement is true?

A

Time of flight of both projectile is same

B

Maximum height acquired by both projectiles is same

C

Horizontal range of both projectiles is Same

D

None of these

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The correct Answer is:
To solve the problem of determining which statement is true regarding two projectiles thrown at angles of 50° and 40° with the same speed, we can analyze the projectile motion equations step by step. ### Step 1: Understanding Time of Flight The time of flight (T) for a projectile is given by the formula: \[ T = \frac{2u \sin \theta}{g} \] where: - \( u \) is the initial speed, - \( \theta \) is the angle of projection, - \( g \) is the acceleration due to gravity. For the two angles: - Time of flight for 50°: \[ T_{50} = \frac{2u \sin 50°}{g} \] - Time of flight for 40°: \[ T_{40} = \frac{2u \sin 40°}{g} \] Since \( \sin 50° \) is not equal to \( \sin 40° \), we can conclude: \[ T_{50} \neq T_{40} \] Thus, the first statement is false. ### Step 2: Analyzing Maximum Height The maximum height (H) of a projectile is given by the formula: \[ H = \frac{u^2 \sin^2 \theta}{2g} \] For the two angles: - Maximum height for 50°: \[ H_{50} = \frac{u^2 \sin^2 50°}{2g} \] - Maximum height for 40°: \[ H_{40} = \frac{u^2 \sin^2 40°}{2g} \] Since \( \sin^2 50° \) is not equal to \( \sin^2 40° \), we conclude: \[ H_{50} \neq H_{40} \] Thus, the second statement is also false. ### Step 3: Evaluating Horizontal Range The horizontal range (R) of a projectile is given by the formula: \[ R = \frac{u^2 \sin 2\theta}{g} \] For the two angles: - Range for 50°: \[ R_{50} = \frac{u^2 \sin 100°}{g} \] - Range for 40°: \[ R_{40} = \frac{u^2 \sin 80°}{g} \] Using the identity \( \sin(90° - \theta) = \cos(\theta) \), we can see that: - \( \sin 100° = \sin(90° + 10°) = \cos 10° \) - \( \sin 80° = \sin(90° - 10°) = \cos 10° \) Since \( \sin 100° = \sin 80° \), we find: \[ R_{50} = R_{40} \] Thus, the third statement is true. ### Conclusion The correct statement is that the horizontal range of both projectiles is the same.
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