A block is lying static on the floor. The maximum value of static fictional force on the block is 10 N. If a horizontal force of 6 N is applied to the block,what will be the frictional force on the block?

Options

A. 2 N
B. 18 N
C. 6 N
D. 10 N

Answer

To solve the problem step by step, we need to analyze the forces acting on the block and the nature of static friction.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- The maximum static frictional force (limiting friction) is given as \( F_{\text{max}} = 10 \, \text{N} \).
- A horizontal force \( F_{\text{applied}} = 6 \, \text{N} \) is applied to the block.

2. **Understand the Nature of Static Friction:**
- Static friction is a self-adjusting force that prevents an object from moving when an external force is applied. It can vary from \( 0 \, \text{N} \) up to its maximum value, which is \( 10 \, \text{N} \) in this case.

3. **Determine the Frictional Force:**
- Since the applied force \( 6 \, \text{N} \) is less than the maximum static friction \( 10 \, \text{N} \), the block will not move.
- The static frictional force will adjust itself to match the applied force to keep the block at rest. Therefore, the frictional force \( F_{\text{friction}} \) will be equal to the applied force.

\[ F_{\text{friction}} = F_{\text{applied}} = 6 \, \text{N} \]

4. **Conclusion:**
- The frictional force acting on the block is \( 6 \, \text{N} \).

### Final Answer:
The frictional force on the block is \( 6 \, \text{N} \).

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