A particle of mass m is moving in a circle of radius (r) with changing speed (v) the direction of centripetal force and tangential force are shown below the value of `alpha` is

Options

A. `alpha= tan^-1(((dv)/dt)/(v^2/r))`
B. `alpha= cos^-1(((dv)/dt)/(v^2/r))`
C. `alpha= sin^-1((v^2/r)/((dv)/dt))`
D. `alpha= tan^-1((v^2/r)/((dv)/dt))`

Answer

A