Home
Class 12
PHYSICS
If 5 small spherical droplet coalesce to...

If 5 small spherical droplet coalesce to form a bigger drop then temperature of bigger drop in comparison to smaller drops will

A

Decrease

B

Remain same

C

May increase or decrease

D

Increase

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how the temperature of a bigger drop compares to that of smaller drops when five small spherical droplets coalesce, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Volume Conservation**: - When five small droplets coalesce to form a larger droplet, the total volume before and after the coalescence remains the same. - Let the radius of each smaller droplet be \( R_0 \). The volume \( V_0 \) of one small droplet is given by: \[ V_0 = \frac{4}{3} \pi R_0^3 \] - Therefore, the total volume of five small droplets is: \[ V_{\text{total}} = 5 \times V_0 = 5 \times \frac{4}{3} \pi R_0^3 = \frac{20}{3} \pi R_0^3 \] 2. **Volume of the Bigger Drop**: - Let the radius of the bigger droplet be \( R \). The volume \( V \) of the bigger droplet is: \[ V = \frac{4}{3} \pi R^3 \] - Setting the total volume equal to the volume of the bigger droplet, we have: \[ \frac{20}{3} \pi R_0^3 = \frac{4}{3} \pi R^3 \] - Canceling \( \frac{4}{3} \pi \) from both sides gives: \[ 5 R_0^3 = R^3 \] 3. **Finding the Radius of the Bigger Drop**: - Taking the cube root of both sides, we find: \[ R = (5)^{1/3} R_0 \] 4. **Relating Volume and Temperature**: - According to the ideal gas law, for a given amount of gas at constant pressure, the volume \( V \) is directly proportional to the temperature \( T \): \[ V \propto T \] - Since the volume of the bigger droplet is greater than that of the smaller droplets (as \( R > R_0 \)), we can conclude that: \[ V_{\text{bigger}} > V_{\text{smaller}} \implies T_{\text{bigger}} > T_{\text{smaller}} \] 5. **Conclusion**: - Therefore, the temperature of the bigger drop \( T \) will be greater than the temperature of the smaller drops \( T_0 \): \[ T > T_0 \] ### Final Answer: The temperature of the bigger drop in comparison to the smaller drops will be higher.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOCK TEST 14

    AAKASH INSTITUTE ENGLISH|Exercise Example|20 Videos
  • MOCK TEST 16

    AAKASH INSTITUTE ENGLISH|Exercise Example|18 Videos

Similar Questions

Explore conceptually related problems

When water droplets merge to form a bigger drop

When water droplets merge to form a bigger drop

1000 tiny mercury droplets coalesce to form a bigger drop .In this process , the temperature of the drop

If n drops, each of capacitance C and charged to a potential V, coalesce to form a big drop, the ratio of the energy stored in the big drop to that in each small drop will be

Two drops of equal radius coalesce to form a bigger drop. What is ratio of surface energy of bigger drop to smaller one?

Eight drops of mercury of equal radii possessing equal charges combine to from a big drop. Then the capacitance of bigger drop compared to each individual small drop is

Eight drops of mercury of equal radii possessing equal charges combine to from a big drop. Then the capacitance of bigger drop compared to each individual small drop is

If two identical mercury drops are combined to form a single drop, then its temperature will

Eight small drops, each of radius r and having same charge q are combined to form a big drop. The ratio between the potentials of the bigger drop and the smaller drop is

If n drops of a liquid, form a single drop, then