A gas expands from `2m^3` to `2.5m^3` at constant pressure `10^3` pa, the work done is

Options

A. 50 J
B. 25 J
C. 500 J
D. 250 J

Answer

To solve the problem of calculating the work done by a gas during an isobaric expansion, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Initial volume, \( V_i = 2 \, m^3 \)
- Final volume, \( V_f = 2.5 \, m^3 \)
- Constant pressure, \( P = 10^3 \, Pa \)

2. **Calculate the Change in Volume:**
\[ \Delta V = V_f - V_i = 2.5 \, m^3 - 2 \, m^3 = 0.5 \, m^3 \]

3. **Use the Formula for Work Done in Isobaric Process:**
The work done \( W \) during an isobaric process is given by the formula:
\[ W = P \Delta V \]

4. **Substitute the Values into the Formula:**
\[ W = (10^3 \, Pa) \times (0.5 \, m^3) \]

5. **Calculate the Work Done:**
\[ W = 10^3 \times 0.5 = 500 \, J \]

### Final Answer:
The work done by the gas during the expansion is \( 500 \, J \).

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