If the incident ray falls normally on the refracting surface then

Options

A. Refraction do not take place
B. Refraction take place with little bending
C. Refraction takes place without bending
D. Reflection takes place

Answer

To solve the question, we will analyze the behavior of light when it strikes a refracting surface normally (perpendicularly).

### Step-by-Step Solution:

1. **Understanding Normal Incidence**:
- When a light ray strikes a surface normally, it means that the angle of incidence (i) is 0 degrees. This is because normal incidence refers to the ray hitting the surface at a right angle (90 degrees to the surface).

2. **Applying the Concept of Refraction**:
- Refraction occurs when light passes from one medium to another and changes speed, which causes it to change direction. However, if the light strikes the surface normally, there is no change in direction.

3. **Using Snell's Law**:
- Snell's Law states that:
\[ \mu_1 \sin(i) = \mu_2 \sin(r) \]
- Here, \( \mu_1 \) and \( \mu_2 \) are the refractive indices of the two media, \( i \) is the angle of incidence, and \( r \) is the angle of refraction.

4. **Substituting Values**:
- Since the angle of incidence \( i = 0 \):
\[ \mu_1 \sin(0) = \mu_2 \sin(r) \]
- This simplifies to:
\[ 0 = \mu_2 \sin(r) \]
- For this equation to hold true, \( \sin(r) \) must also be 0, which implies that \( r = 0 \) degrees.

5. **Conclusion**:
- Since both the angle of incidence and the angle of refraction are 0 degrees, the light ray passes through the refracting surface without any bending. Thus, we conclude that refraction takes place without bending.

6. **Final Answer**:
- The correct option is: **Refraction takes place without bending**.