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The de-Broglie wavelength of an electron...

The de-Broglie wavelength of an electron accelerated by and electric potential of V volts is given by:

A

`lambda=12.27/√v cm`

B

`lambda=12.27/√v mm`

C

`lambda=12.27/√v cm`

D

`lambda=12.27/√v A`

Text Solution

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The correct Answer is:
D
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