Explain photoelectric effect Explain the effect of increase of intensity of incident radiations on photoelectrons emitted by a photo-tube.

Options

A. increases
B. decreases
C. remains constant
D. first decrease and then increase constant

Answer

### Step-by-Step Solution

1. **Understanding the Photoelectric Effect**:
- The photoelectric effect is a phenomenon where electrons are emitted from a material (usually a metal) when it is exposed to electromagnetic radiation, such as light. This effect demonstrates the particle-like behavior of light, which consists of discrete packets of energy called photons.

2. **Photon Interaction with Metal**:
- When photons strike the surface of a metal, they can transfer their energy to the electrons in the metal. If the energy of the incoming photon is greater than the work function (the minimum energy required to remove an electron from the metal), the electron can escape from the surface. The emitted electrons are referred to as photoelectrons.

3. **Experimental Setup**:
- In a typical experimental setup, a photo-tube is used where a metal surface is exposed to light. When the light (radiation) strikes the metal surface, photoelectrons are emitted.

4. **Effect of Increasing Intensity of Incident Radiation**:
- The intensity of the incident radiation refers to the number of photons striking the surface per unit time. When the intensity of the radiation increases, more photons are available to interact with the electrons in the metal.

5. **Emission of Photoelectrons**:
- As the intensity increases, the number of photons hitting the metal surface increases, leading to a higher number of electrons being emitted, provided that the energy of the photons is sufficient to overcome the work function of the metal. Thus, the rate of photoelectron emission increases with the increase in intensity of the incident radiation.

6. **Conclusion**:
- In summary, the photoelectric effect illustrates how light can cause the emission of electrons from a material. Increasing the intensity of the incident radiation results in a greater number of emitted photoelectrons, as more photons are available to interact with the electrons in the metal.