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Find the maximum velocity of an electron...

Find the maximum velocity of an electron emitted by light of wavelength `lambda` incident on the surface of a metal of work function `phi`.

A

`v=[2m_e lambda/(hc-lambda phi)]^(12)`

B

`v=[2hc/(m_e lambda-phi)]^(12)`

C

`v=[m_e lambda/(hc+lambda phi)]^(12)`

D

`v=[2(hc-lambda phi)/(m_e lambda)]^(12)`

Text Solution

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The correct Answer is:
D
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