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The correct thermodynamic conditions for...

The correct thermodynamic conditions for the spontaneous reaction at all temperature is

A

`deltaH gt 0, deltaS lt 0`

B

`deltaH lt 0, deltaS gt 0`

C

`deltaH gt 0, deltaS gt 0`

D

`deltaH lt 0, deltaS lt 0`

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Free enegry , G = H - TS , is state function that indicates whther a reaction is spontaneous or non-spontaneous. If you think of TS as the part of the system's enegry that is disordered already, then (H -TS) is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered. Also, DeltaG = DeltaH - T DeltaS From the second law of thermodynamics, a reaction is spontaneous if Delta_("total")S is positive, non-spontaneous if Delta_("total")S is negative, and at equilibrium if Delta_('total")S is zero. Since, -T DeltaS = DeltaG and since DeltaG and DeltaS have opposite sings, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure. IF DeltaG lt 0 , the reaction is spontaneous. If DeltaG gt 0 , the reaction is non-spontaneous. If DeltaG = 0 , the reaction is at equilibrium. Read the above paragraph carefully and answer the following questions based on the above comprehension. For the spontaneity of a reaction, which statement is true?

Free enegry , G = H - TS , is state function that indicates whther a reaction is spontaneous or non-spontaneous. If you think of TS as the part of the system's enegry that is disordered already, then (H -TS) is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered. Also, DeltaG = DeltaH - T DeltaS From the second law of thermodynamics, a reaction is spontaneous if Delta_("total")S is positive, non-spontaneous if Delta_("total")S is negative, and at equilibrium if Delta_('total")S is zero. Since, -T DeltaS = DeltaG and since DeltaG and DeltaS have opposite sings, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure. IF DeltaG lt 0 , the reaction is spontaneous. If DeltaG gt 0 , the reaction is non-spontaneous. If DeltaG = 0 , the reaction is at equilibrium. Read the above paragraph carefully and answer the following questions based on the above comprehension. A particular reaction has a negative value for the free energy change. Then at ordinary temperature

For an endothermic reaction to be spontaneous

Free enegry , G = H - TS , is state function that indicates whther a reaction is spontaneous or non-spontaneous. If you think of TS as the part of the system's enegry that is disordered already, then (H -TS) is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered. Also, DeltaG = DeltaH - T DeltaS From the second law of thermodynamics, a reaction is spontaneous if Delta_("total")S is positive, non-spontaneous if Delta_("total")S is negative, and at equilibrium if Delta_('total")S is zero. Since, -T DeltaS = DeltaG and since DeltaG and DeltaS have opposite sings, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure. IF DeltaG lt 0 , the reaction is spontaneous. If DeltaG gt 0 , the reaction is non-spontaneous. If DeltaG = 0 , the reaction is at equilibrium. Read the above paragraph carefully and answer the following questions based on the above comprehension. If an endothermic reaction is non-spontaneous at freezing point of water and becomes feasible at its boiling point, then

Free enegry , G = H - TS , is state function that indicates whther a reaction is spontaneous or non-spontaneous. If you think of TS as the part of the system's enegry that is disordered already, then (H -TS) is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered. Also, DeltaG = DeltaH - T DeltaS From the second law of thermodynamics, a reaction is spontaneous if Delta_("total")S is positive, non-spontaneous if Delta_("total")S is negative, and at equilibrium if Delta_('total")S is zero. Since, -T DeltaS = DeltaG and since DeltaG and DeltaS have opposite sings, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure. IF DeltaG lt 0 , the reaction is spontaneous. If DeltaG gt 0 , the reaction is non-spontaneous. If DeltaG = 0 , the reaction is at equilibrium. Read the above paragraph carefully and answer the following questions based on the above comprehension. Which of the following is true for the reaction? H_(2)O(l) hArr H_(2)O(g) at 100^(@)C and 1 atmosphere

AAKASH INSTITUTE ENGLISH-TEST 3-EXERCISE
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  2. At high pressure, the compressibility factor for one mole of van der w...

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  3. The correct thermodynamic conditions for the spontaneous reaction at a...

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  5. In the electrolysis of H2O , 11.2 liters of H2 was liberated at cathod...

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  6. Which among the following will boil at highest temperature?

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  7. If 200 ml of 0.1 MH2SO4 solution is mixed with 200 ml of 0.15 M NaOH s...

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  8. Unit of surface tension is

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  9. For which of the following processes, entropy change is negative?

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  10. A liquid is in equilibrium with its vapour at a certain temperature. I...

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  11. The work done by one mole of ideal gas when its teperature is increase...

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  12. Standard enthalpy of formation is zero for

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  13. Ratio of the rate of effusion of oxygen gas at 1.5 atm to that of heli...

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  14. Compressibility factor under critical state of a gas is

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  15. An air bubble formed under water at temperature 17^oC and the pressure...

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  16. A gaseous mixture contains 220 g of carbon dioxide and 280 g of nitrog...

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  17. If the enthalpies of formation of C3H8(g), CO2(g) and H2O(l) at standa...

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  18. When 5 moles of an ideal gas is expended at 350 K reversibly from 5 L ...

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  19. When 1.5 mol of a gas is heated at constant volume from 300 K to 350 K...

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  20. For which of the following reactions, deltaH = deltaU?

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